The principal organic product formed in the reaction given below is
$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$
$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$
- A$CH_3-CHBr(CH_2)_8COOH$
- B$CH_2 = CH(CH_2)_8COBr$
- C$BrCH_2-CH_2(CH_2)_8COOH$
- D$CH_2 = CH(CH_2)_7CHBrCOOH$
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